2[x-(2x+3)+1]=2(x+2)

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Solution for 2[x-(2x+3)+1]=2(x+2) equation:


Simplifying
2[x + -1(2x + 3) + 1] = 2(x + 2)

Reorder the terms:
2[x + -1(3 + 2x) + 1] = 2(x + 2)
2[x + (3 * -1 + 2x * -1) + 1] = 2(x + 2)
2[x + (-3 + -2x) + 1] = 2(x + 2)

Reorder the terms:
2[-3 + 1 + x + -2x] = 2(x + 2)

Combine like terms: -3 + 1 = -2
2[-2 + x + -2x] = 2(x + 2)

Combine like terms: x + -2x = -1x
2[-2 + -1x] = 2(x + 2)
[-2 * 2 + -1x * 2] = 2(x + 2)
[-4 + -2x] = 2(x + 2)

Reorder the terms:
-4 + -2x = 2(2 + x)
-4 + -2x = (2 * 2 + x * 2)
-4 + -2x = (4 + 2x)

Solving
-4 + -2x = 4 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-4 + -2x + -2x = 4 + 2x + -2x

Combine like terms: -2x + -2x = -4x
-4 + -4x = 4 + 2x + -2x

Combine like terms: 2x + -2x = 0
-4 + -4x = 4 + 0
-4 + -4x = 4

Add '4' to each side of the equation.
-4 + 4 + -4x = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -4x = 4 + 4
-4x = 4 + 4

Combine like terms: 4 + 4 = 8
-4x = 8

Divide each side by '-4'.
x = -2

Simplifying
x = -2

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